Question

The drama club is selling tickets to their play to raise money for the show's expenses.

Each student ticket sells for $5 and each adult ticket sells for $9. The auditorium can
hold a maximum of 122 people. The drama club must make no less than $890 from
ticket sales to cover the show's costs. If 45 student tickets were sold, determine the
minimum number of adult tickets that the drama club must sell in order to meet the
show's expenses. If there are no possible solutions, submit an empty answer.
Answer:
Submit Answer

Answer 1

Answer:76

Explanation:

let the number of student tickets be x. Let the adult tickets be y.

5x+9y

The drama club needs to raise no less than $890, this would be > with a line under.

The full first equation would be- 5x+ 9y> 890
The second equation would be- x + y< 122

Because x is the number of students and y is the number of adults the sum of the two numbers cannot be more than 122 because that is the number of seats.

If we already know there are 42 students we can replace the x with 42 this would look like-

5(42)+9y > 890
42+y < 122

- plug into graphing calculator
Look at a graph( I recommend Desmos) and figure out what the bottom number is, even if it looks like it’s 75 its 76 because-

42+76=118 118 is less than 122

5(42)=219 9(76)=684 684+219=903 903 is more than 890

The minimum number of adults that could go would be 76.