92,674 views
22 votes
22 votes
Solve the inequality
8+3x<20

User Mike Gold
by
2.4k points

2 Answers

10 votes
10 votes


\huge\text{Hey there!}


\mathsf{8 + 3x < 20}


\mathsf{3x + 8 < 20}


\text{Subtract by 8 to both sides}


\mathsf{3x + 8 - 8 < 20 - 8}}


\text{Simplify it}


\mathsf{3x < 20 - 8}


\mathsf{3x < 12}


\text{Divide 3 to both sides}


\mathsf{(3x)/(3) < (12)/(3)}


\text{Simplify it}


\mathsf{x < (12)/(3)}


\mathsf{x < 4}



\huge\text{Therefore, your answer should be: \boxed{\mathsf{x < 4}}}\huge\checkmark


\rm{You\ have\ an\ O P E N\ circle\ shaded\ to\ the\ left\ }\large\checkmark



\huge\text{Good luck on assignment \&amp; enjoy your day!}


~
\frak{Amphitrite1040;)}

User Yeggeps
by
3.0k points
17 votes
17 votes

Answer:

x < 4

Explanation:

8 + 3x < 20 ( subtract 8 from both sides )

3x < 12 ( divide both sides by 3 )

x < 4

User Nikolaus
by
2.5k points