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An animal researcher randomly selected 98 dogs and cats and recorded if they napped between 2:00 p. M. And 2:30 p. M. The two-way table displays the data.

A 4-column table with 3 rows. Column 1 has entries dog, cat, total. Column 2 is labeled nap with entries 15, 23, 38. Column 3 is labeled no nap with entries 32, 28, 60. Column 4 is labeled total with entries 47, 51, 98. The columns are titled napping habit and the rows are titled animal type.



Suppose an animal is randomly selected. Let event C = cat and let event N = nap. What is the value of P(C|N)?



StartFraction 38 Over 98 EndFraction


StartFraction 23 Over 51 EndFraction


StartFraction 47 Over 98 EndFraction


StartFraction 23 Over 38 EndFraction

User Zerowalker
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2 Answers

1 vote

Final answer:

The value of P(C|N), the probability that a randomly selected napping animal is a cat, is calculated using the formula P(C|N) = P(C ∩ N) / P(N). The correct value is 23 napping cats divided by the total 38 napping animals, resulting in a probability of 23/38.

Step-by-step explanation:

The question is asking us to calculate the conditional probability of a randomly selected animal being a cat, given that it does nap between 2:00 p.m. and 2:30 p.m. This conditional probability is denoted as P(C|N), where C is the event that an animal is a cat, and N is the event that the animal naps. To find this, we use the formula for conditional probability, P(C|N) = P(C ∩ N) / P(N), where P(C ∩ N) is the probability that the animal is both a cat and naps, and P(N) is the probability that the animal naps regardless of being a cat or dog.

From the two-way table, there are 23 cats that nap and there are a total of 38 animals that nap. The probability that a randomly selected napping animal is a cat is therefore the number of napping cats divided by the total number of napping animals, which is 23/38. None of the other options correctly represent this probability.

User Justin Moh
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2 votes

Final Answer:

The value of ( P(C|N) ), the probability of selecting a cat given that the animal napped, is
\( (23)/(38) \).

Step-by-step explanation:

The conditional probability ( P(C|N) ) represents the probability of an event occurring given that another event has already occurred. In this case, it is the probability of selecting a cat (C) given that the animal napped (N). To calculate this, we use the formula:


\[ P(C|N) = (P(C \cap N))/(P(N)) \]

where
\(P(C \cap N)\) is the probability of both events happening, and (P(N)) is the probability of the given event (nap) occurring.

From the table,
\(P(C \cap N)\) is the number of cats that napped, which is 23, and (P(N)) is the total number of animals that napped, which is 38. Therefore,


\[ P(C|N) = (23)/(38) \]

So, the correct answer is
\( (23)/(38) \). This indicates that, given an animal napped between 2:00 p.m. and 2:30 p.m., there is a
\( (23)/(38) \) probability that it is a cat.

In summary, the probability ( P(C|N) ) is calculated by dividing the number of cats that napped by the total number of animals that napped. This ratio gives the likelihood of a randomly selected napping animal being a cat.

User Jared S
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8.1k points