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Given a circle of radius 21cm correct to the nearest cm. What is the possible maximum error when calculating its area?

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Answer:

:)

Explanation:

This is a calculus problem that involves using differentials to estimate the maximum error in the area of a circle given the error in its radius. According to 1, the errors are related by ΔA=drdAΔr=2πrΔr

Therefore, Δr=2πrΔA

If the radius is 21 cm correct to the nearest cm, then the possible error in the radius is ±0.5 cm. Using this value in the formula above, we get ΔA=2π(21)(0.5)≈65.97 cm2

This is the possible maximum error when calculating the area of a circle with radius 21 cm correct to the nearest cm.

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