Question

Given that
(2y+2)
(4x-32) is a null vector find x and y

Answer 1

-

—4<x<8

Explanation:

Given that,

x2−4x−32

⇒x2−(8−4)x−32

⇒x2−8x+4x−32

⇒x(x−8)+4(x−8)

⇒(x−8)(x+4)

Hence, −4<x<8