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Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of

130 millimeters, and a standard deviation of 6 millimeters. If a random sample of 49 steel bolts is selected, what is the probability that the sample mean would be greater than 132.3 millimeters? Round your answer to four decimal places.

User Oftedal
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Answer: To solve this problem, we can use the Central Limit Theorem. The Central Limit Theorem states that the distribution of sample means from a large enough sample follows a normal distribution, regardless of the shape of the population distribution, as long as the sample size is sufficiently large.

Given:

Mean diameter of steel bolts = 130 millimeters

Standard deviation = 6 millimeters

Sample size = 49

Sample mean we are interested in = 132.3 millimeters

To calculate the probability that the sample mean would be greater than 132.3 millimeters, we need to calculate the z-score and then find the corresponding probability from the standard normal distribution table.

First, we calculate the standard error (SE) using the formula:

SE = Standard deviation / √(Sample size)

SE = 6 / √49

SE = 6 / 7

SE ≈ 0.8571

Next, we calculate the z-score using the formula:

z = (Sample mean - Population mean) / SE

z = (132.3 - 130) / 0.8571

z ≈ 3.0995

Using the z-score table or a calculator, we find that the probability corresponding to a z-score of 3.0995 is approximately 0.9987.

Therefore, the probability that the sample mean would be greater than 132.3 millimeters is approximately 0.9987 (or 99.87% when rounded to four decimal places).

User Robert Dale Smith
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