Question

If 980 = 2x X 5y X 7z, find the values of x, y and z... pls help with working​

Answer 1

• x = 2, y = 1, z = 7

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We are given that, 980 = 2x × 5y × 7z

We need to find the values of x, y, and z.

Find the prime factorization of 980.

980 can be written as:

• 980 = 2 × 2 × 5 × 7 × 7

Compare the given expression with the prime factorization of 980.

• 2 × 2 × 5 × 7 × 7 = 2x × 5y × 7z

It can be observed that:

• 2x = 2 × 2 ⇒ x = 2
• 5y = 5 ⇒ y = 1
• 7z = 7 × 7 ⇒ z = 7

Hence, the values of x, y, and z are 2, 1, and 7 respectively.