Question

What is the mass in grams of 2. 00 × 105 atoms of naturally occurring neon?.

Answer 1

`6.70x10^(-18)` g

Step-by-step explanation:

The molar mass of naturally occurring neon (Ne) is approximately 20.18 grams/mol.

To calculate the mass of
`2.00x10^5` atoms of neon, we can use the following steps:

Determine the number of moles: Divide the number of atoms by Avogadro's number (
`6.022x10^(23)` Atoms/MOL).

Number of moles = (
`2.00x10^5` atoms) / (
`6.022 x10^(23)` atoms/mol)

Calculate the mass: Multiply the number of moles by the molar mass of neon.

Mass = (Number of moles) × (Molar mass of neon)

Using the above steps, we can calculate the mass as follows:

Number of moles = (
`2.00x10^5` atoms) / (
`6.022 x10^(23)` atoms/mol)

≈
`3.32x10^(-19)` moles

Mass = (
`3.32x10^(-19)` moles) × (20.18 grams/mol)

≈
`6.70x10^(-18)` grams

Therefore, the mass of
`2.00x10^5` Atoms of naturally occurring neon is approximately
`6.70x10^(-18)` Grams.