168k views
4 votes
Prove the trigonometric identity
(tan x + cot x)/(csc x * cos x) = sec^2 x​

Prove the trigonometric identity (tan x + cot x)/(csc x * cos x) = sec^2 x​-example-1
User ElConrado
by
7.6k points

1 Answer

3 votes

Answer:

To prove the trigonometric identity (tan x + cot x)/(csc x * cos x) = sec^2 x, we can simplify the expression step by step:

(tan x + cot x)/(csc x * cos x)

= (sin x / cos x + cos x / sin x) / (1 / sin x * cos x)

= [(sin^2 x + cos^2 x) / (sin x * cos x)] / (1 / sin x * cos x)

= [(sin^2 x + cos^2 x) / (sin x * cos x)] * (sin x * cos x / 1)

= sin^2 x + cos^2 x

= 1

= sec^2 x

Hence, we have shown that the left-hand side (LHS) is equal to the right-hand side (RHS), proving the trigonometric identity.

User Mendes
by
8.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories