Question

A plane accelerates from rest at a constant rate of 5. 00 m/s^2 along a runway that is 1800 m long. Assume that the plane reaches the required takeoff velocity at the end of the runway. What is the time to needed to take off?.

Answer 1

Answer: therefore it will take 60 seconds for the plane to take off

Explanation: We can use the following kinematic equation:

distance = initial velocity * time + 1/2 * acceleration * time^2

where:

distance = 1800 m

initial velocity = 0 m/s (the plane starts from rest)

acceleration = 5.00 m/s^2

Solving for time, we get:

time = sqrt(2 * distance / acceleration)

time = sqrt(2 * 1800 / 5.00) = 60 s