Answer: therefore it will take 60 seconds for the plane to take off
Explanation: We can use the following kinematic equation:
distance = initial velocity * time + 1/2 * acceleration * time^2
where:
distance = 1800 m
initial velocity = 0 m/s (the plane starts from rest)
acceleration = 5.00 m/s^2
Solving for time, we get:
time = sqrt(2 * distance / acceleration)
time = sqrt(2 * 1800 / 5.00) = 60 s