Question

In a bag there are 5 yellow marbles, 7 green marbles, 2 white marbles, and 6 blue marbles. IfT take 3 marbles without replacing them what is the probability of getting 2 white and a blue marble?

Answer 1

1/190

Explanation:

To calculate the probability of drawing 2 white marbles and 1 blue marble without replacement, we need to consider the total number of ways to choose 3 marbles out of the total number of marbles in the bag.

The total number of marbles in the bag is 5 + 7 + 2 + 6 = 20.

First, let's calculate the number of ways to choose 2 white marbles out of the 2 available:

Number of ways to choose 2 white marbles = (2 choose 2) = 1

Next, we need to calculate the number of ways to choose 1 blue marble out of the 6 available:

Number of ways to choose 1 blue marble = (6 choose 1) = 6

Now, we can calculate the total number of ways to choose 3 marbles out of the 20 marbles in the bag:

Total number of ways to choose 3 marbles = (20 choose 3) = 1140

Finally, we can calculate the probability by dividing the number of favorable outcomes (2 white marbles and 1 blue marble) by the total number of possible outcomes:

Probability = (Number of favorable outcomes) / (Total number of possible outcomes)

= (1 * 6) / 1140

= 6 / 1140

= 1 / 190