30.0k views
0 votes
Mr. Duong is riding the Drop Zone at Kemah. If Mr. Duong free falls for 5 seconds, how far will he fall? Hint: Gravity is 9. 8 m/s2.

142. 5 m

42. 5 m

100. 5 m

22. 5 m

122. 5

1 Answer

4 votes

Answer:


122.5\; {\rm m} assuming that the rider was initially not moving.

Step-by-step explanation:

Since the rider is in a free fall, acceleration of the rider would be
g = 9.8\; {\rm m\cdot s^(-2)}.

The goal is to find the distance
x travelled during a given period of time. To do so, apply the following SUVAT equation:


\displaystyle x = (1)/(2)\, a\, t^(2) + u\, t,

Where:


  • a = g = 9.8\; {\rm m\cdot s^(-2)} since the rider is in a free fall,

  • t = 5\; {\rm s} is the duration of the free fall, and

  • u = 0\; {\rm m\cdot s^(-1)} is the initial velocity of the rider at the beginning of the free fall- assuming that the rider was initially not moving.

Substitute in
t = 5\; {\rm s} and evaluate to find this displacement:


\begin{aligned}x &= (1)/(2)\, a\, t^(2) + u\, t \\ &= \left((1)/(2)\, (9.8)\, (5)^(2) + (0)\, (5)\right) \; {\rm m\cdot s^(-1)} \\ &= 122.5\; {\rm m} \end{aligned}.

User Ketan Malhotra
by
7.9k points