Question

a 2500 kg car accelerates from rest to a velocity of 10 m/s in 5.0 seconds. the average power of the engine during this acceleration is

Answer 1

To find the average power of the engine during the acceleration, we can use the formula:

Power = Work / Time

The work done on the car is equal to the change in kinetic energy. The change in kinetic energy can be calculated using the formula:

ΔKE = (1/2) * m * (v_f^2 - v_i^2)

where:

m = mass of the car = 2500 kg

v_i = initial velocity = 0 m/s (since the car starts from rest)

v_f = final velocity = 10 m/s

ΔKE = (1/2) * 2500 kg * (10 m/s)^2

ΔKE = 125,000 J

Now, we can substitute the values into the power formula:

Power = ΔKE / Time = 125,000 J / 5.0 s

Power = 25,000 Watts

Therefore, the average power of the engine during the acceleration is 25,000 Watts.