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I would like to know the answer for this question-example-1

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Answer:

Option A

Explanation:

Equation of line in slope-intercept form:

Pick any two points on the line.

(3 , 0) ⇒ x₁ = 3 & y₁ = 0

(0,-2) ⇒ x₂ = 0 & y₂ = -2

Find the slope using the formula,


\boxed{\bf Slope =(y_2-y_1)/(x_2-x_1)}


\sf =(-2-0)/(0-3)\\\\\\=(-2)/(-3)\\\\\\=(2)/(3)

Slope-point form of a line: y - y₁ = m(x - x₁)

Substitute slope and the point in the above equation,


y - 0 = (2)/(3)(x - 3)\\\\ ~~~~~~ y= (2)/(3)x-(2)/(3)*3\\\\\\~~~~~~\boxed{ y = (2)/(3)x-2}

This is in slope intercept form: y = mx + b.

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