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A pendulum is made by tying a 75 g ball to a 130-cm long string. The ball is pulled 5.0 degrees to the side and released.

How many times does the ball pass through the lowest point of its arc in 9.8 s?

User AndrewR
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1 Answer

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Final answer:

The ball passes through the lowest point of its arc 4 times in 9.8 seconds.

Step-by-step explanation:

The number of times the ball passes through the lowest point of the arc in 9.8 seconds can be determined using the formula for the period of a pendulum. The period, T, of a pendulum, is given by the formula T = 2π√(L/g), where L is the length of the string and g is the acceleration due to gravity. In this case, L = 130 cm = 1.3 m and g = 9.8 m/s². First, calculate the period using the given values:

T = 2π√(1.3/9.8)

T = 2π x 0.36

T = 2.26 seconds

Next, calculate the number of periods in 9.8 seconds:

Number of periods = 9.8 / 2.26 = 4.33

Rounding to the nearest whole number, the ball passes through the lowest point of its arc 4 times in 9.8 seconds.

User Explodes
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