Question

Find the side AB in triangle ABC

Answer 1

The answer is approximately 14

Explanation:

<A+<B+<C=180

y+37+90=180

y+127=180

y=180-127

y=53°

<A=53°

sinø=opp/hyp

sin67=11/x

x=11/sin53°

x≈14

Answer 2

`\cos(37^o )=\cfrac{\stackrel{adjacent}{11}}{\underset{hypotenuse}{x}} \implies x=\cfrac{11}{\cos(37^o)}\implies x\approx 13.77`

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