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If a 50 N block is resting on a steel table with a coefficient of static friction 0.74, then what minimum force is required to move the block?

(100 points) HELP ASAP

User Miger
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Answer:To determine the minimum force required to move the block, we need to consider the static friction acting on the block. The static friction force can be calculated using the formula:

f_s = μ_s * N

where f_s is the static friction force, μ_s is the coefficient of static friction, and N is the normal force.

In this case, the normal force N is equal to the weight of the block, which is given as 50 N.

Substituting the values into the formula, we have:

f_s = 0.74 * 50

f_s = 37 N

Therefore, the minimum force required to move the block is 37 N.

User Michel Feldheim
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