Answer:
Ok, sure.
Explanation:
Let's denote the cost of a parking ticket as "P" and the cost of a traffic violation as "T".
From the information provided, we can create the following equations:
Equation 1: 3P + 14T = 2030 (for the first month)
Equation 2: 11P + 11T = 2200 (for the second month)
We now have a system of equations to solve. We can use various methods to find the values of P and T.
One common method is to use substitution. We can solve Equation 1 for P and substitute it into Equation 2:
From Equation 1, we can isolate P:
3P = 2030 - 14T
P = (2030 - 14T) / 3
Substituting P into Equation 2:
11((2030 - 14T) / 3) + 11T = 2200
Now, we can solve this equation to find the value of T.
11(2030 - 14T) + 33T = 6600
22330 - 154T + 33T = 6600
22330 - 121T = 6600
-121T = 6600 - 22330
-121T = -15730
T = -15730 / -121
T ≈ 130
Now that we have the value of T, we can substitute it back into Equation 1 to find the value of P:
3P + 14(130) = 2030
3P + 1820 = 2030
3P = 2030 - 1820
3P = 210
P = 210 / 3
P = 70
Therefore, each parking ticket costs $70, and each traffic violation costs $130.