188,453 views
2 votes
2 votes
When 1 mole of calcium carbonate (CaCO3) decomposes to form calcium oxide (CaO) and carbon dioxide (CO2) +177.8kJ of heat is absorbed. The equation for this reaction is given below: CaCO3(s) → CaO(s) + CO2(g)Hr = +177.8kJ

The value Hr = +177.8kJ represents the enthalpy of reaction. Provide a definition of the ‘standard enthalpy of reaction’ using this example specifically.

User Robert Picard
by
2.2k points

1 Answer

13 votes
13 votes

The standard enthalpy of reaction (also known as the heat of reaction) is the change in enthalpy that occurs when a chemical reaction takes place under standard conditions. Standard conditions refer to a specific set of conditions, including a temperature of 25°C (298 K) and a pressure of 1 atmosphere (101.3 kPa).

In the case of the reaction CaCO3(s) → CaO(s) + CO2(g), the standard enthalpy of reaction would be the change in enthalpy that occurs when 1 mole of calcium carbonate decomposes to form 1 mole of calcium oxide and 1 mole of carbon dioxide, under standard conditions. The value Hr = +177.8kJ represents the enthalpy of reaction under these conditions.

In general, the standard enthalpy of reaction is a measure of the amount of heat absorbed or released during a chemical reaction under standard conditions. It is expressed in units of energy per mole of reactants or products. Positive values indicate that heat is absorbed during the reaction (endothermic), while negative values indicate that heat is released during the reaction (exothermic).

User Glocore
by
3.4k points