Final answer:
In the CSMA/CD algorithm, after a collision, nodes A and B choose different values of K. Node B schedules its retransmission at t=735 bit times, while Node A starts transmission after the signal from Node B reaches it at t=490 bit times. There will be no collision at the retransmission time of Node A.
Step-by-step explanation:
In the given scenario, nodes A and B collided and detect the collision after a propagation delay of 245 bit times. Node A chooses K=0 for retransmission while Node B chooses K=1. With CSMA/CD protocol, after the collision, both nodes have to wait for an idle channel before retransmitting.
Since Node B chose K=1, it waits for an extra slot time compared to Node A. In this case, a slot time is equal to a propagation delay of 245 bit times. Therefore, Node B schedules its retransmission at t=245 + (1 + 1) * 245 = 735 bit times.
On the other hand, Node A starts its retransmission after an idle channel is detected, which is when Node B's signal reaches Node A. The time it takes for Node B's signal to reach Node A is equal to the propagation delay between the two nodes, which is 245 bit times. Therefore, Node A begins transmission at t = 245 + 245 = 490 bit times.
Since Node B's scheduled retransmission time is later than Node A's transmission time, there will be no collision at the retransmission time of Node A. Node B refrains from transmitting at its scheduled time.