If 20 kg of water at 7 degree celsius with 10 kg of water at 88 degree celsius, find the result and temperature

asked Feb 10, 2024 160k views

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Answer:

T = (m1T1 + m2T2)/(m1 + m2) = (20 * 7 + 10 * 88)/(20 + 10) = 34 °C

Elias Fazel answered Feb 15, 2024

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