Question

Is the potential-energy diagram for a 20 g particle that is released from rest at x = 1.0 m.

Part A
Will the particle move to the right or to the left?
O To the right
O To the left
Part B What is the particle's maximum speed? Express your answer to two significant figures and include the appropriate units.
Vmax =

Part C At what position does it have this speed? Express your answer to two significant figures and include the appropriate units. v =
Part D
Where are the turning points of the motion?
Express your answer using two significant figures. Enter your answers numerically separated by a comma.

Answer 1

Without the provided potential-energy diagram, specific details about the movement, maximum speed, and turning points of a 20 g particle cannot be determined, but general principles about motion in potential energy fields can be applied.

Step-by-step explanation:

The actual potential-energy diagram for the 20 g particle is not provided, so we cannot determine definitively in which direction the particle will move or its maximum speed and position without it. However, we can explain the principles involved:

1. The particle will move from a region of higher potential energy to a region of lower potential energy.
2. The maximum speed will occur where the particle has its minimum potential energy.
3. The turning points are where the particle's potential energy equals its total mechanical energy, at which point it has zero kinetic energy and stops momentarily before reversing direction.

For specifics, you would need to analyze the potential energy curve, which is not provided here.

Answer 2

The potential-energy diagram can determine the motion of a particle. If the potential energy decreases as x increases, the particle will move to the left. If the potential energy increases as x increases, the particle will move to the right. The maximum speed of the particle can be found at the minimum of the potential energy, but specific values are needed to calculate it.

Step-by-step explanation:

The potential-energy diagram can give us information about the motion of the particle. In this case, the particle is released from rest at x=1.0 m. To determine if the particle will move to the right or to the left, we need to look at the shape of the potential energy curve. If the potential energy decreases as x increases, then the force will be in the direction opposite to increasing x, which means the particle will move to the left. If the potential energy increases as x increases, then the force will be in the direction of increasing x, which means the particle will move to the right.

To find the maximum speed of the particle, we need to find the point on the potential energy curve where the kinetic energy is maximum. This occurs at the lowest point on the curve, which is at the minimum of the potential energy. The maximum speed can be calculated using the equation: vmax = sqrt(2 * |Umin| / m), where Umin is the minimum of the potential energy and m is the mass of the particle. In this case, we don't have specific values for the potential energy, so we can't calculate the maximum speed.

Without specific values for the potential energy, we cannot determine the position at which the particle has its maximum speed or the turning points of the motion. We would need the specific shape of the potential energy diagram to answer these questions.