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If molarity of 100 ml glucose is 1.5 then the no of carbon atoms in the solution are

User DavidVII
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Answer:

Molarity =[ number of moles* (1000mL/L)] / volume in mL

Step-by-step explanation:

Given: Molarity =1.5M, volume = 100mL

1.5 =[ (no. of moles) * (1000mL/L) / 100mL

no of moles = (1.5* 100) / 1000

no of moles = 0.15

We know that, 1 mole = 6.023 *10²³ atoms

Since the compound contains 0.15moles, it has

0.15 * 6.023* 110²³

9.0345*10²² atoms of carbon are present in the compound.

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User Ken Bertelson
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