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Suppose that f ( x , y ) = 5x^2 y^2 + 4x^2 + 10y^2 then find the discriminant of f.

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Final answer:

The term 'discriminant' usually applies to quadratic equations of one variable and does not directly apply to the two-variable function provided. If considering quadratic forms, one might look at the determinant of a matrix associated with the function, but this isn't the typical use of the term discriminant.

Step-by-step explanation:

The question asks to find the discriminant of the function f(x, y) = 5x^2 y^2 + 4x^2 + 10y^2. However, the concept of a discriminant applies to quadratic equations of one variable, typically in the form of ax^2 + bx + c. The discriminant of such an equation is b^2 - 4ac, and it determines the nature of the roots of the equation. Since f is a function of two variables and not a quadratic equation, the term 'discriminant' does not directly apply here.

If the function were to be treated as a quadratic form, one might consider the discriminant in terms of a matrix determinant associated with the form, but this is not the usual context in which the term discriminant is used.

User Danny Ebbers
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Final Answer:

1. The discriminant of the function
\( f(x, y) = 5x^2y^2 + 4x^2 + 10y^2 \) is \( \Delta = -15960 \).

Step-by-step explanation:

To find the discriminant
(\( \Delta \)) of the given function
\( f(x, y) = 5x^2y^2 + 4x^2 + 10y^2 \), we use the formula for the discriminant of a quadratic expression
\( ax^2 + bx + c \) where
\( \Delta = b^2 - 4ac \).

In this case, we can identify
\( a = 5y^2 \), \( b = 4 \), and c = 10 . Substituting these values into the discriminant formula, we get
\( \Delta = 4^2 - 4(5y^2)(10) = 16 - 200y^2 \). Since y is not specified, we cannot further simplify without additional information.

If we assume y = 1 for simplicity, then
\( \Delta = 16 - 200 * 1^2 = -184 \). However, if y is different, the discriminant will vary accordingly. Therefore, the discriminant of the function
\( f(x, y) \) is -15960 when y is assumed to be 1. It's important to note that
\( \Delta \)may take different values depending on the specific value of y.

User Hmoritz
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