Question

th silberberg, sample problem 13.5. find the concentration of calcium ion (in ppm) in a 2.94 g pill that contains 45.1 mg of ca2 . enter to 0 decimal places.

Answer 1

To find the calcium ion concentration in ppm, convert the mass of the pill to kilograms, keep the mass of calcium in milligrams, and divide the calcium mass by the pill mass. The result gives the ppm concentration of Ca2+ in the pill.

Step-by-step explanation:

To calculate the concentration of calcium ion (Ca2+) in parts per million (ppm), we have to understand the concept of ppm itself. The ppm is equivalent to milligrams of solute per liter of solution, or in terms of mass, as milligrams of solute per kilogram of solution. In this problem, we need to convert the mass of calcium into mg and the mass of the pill into kg, as ppm is expressed as mg/kg.

First, we convert the mass of the pill to kilograms:

• 2.94 g pill = 0.00294 kg

Next, we use the given mass of Ca2+ which is already in milligrams:

• 45.1 mg of Ca2+

Now, we can calculate the concentration of Ca2+ in ppm:

• ppm of Ca2+ = (45.1 mg Ca2+ / 0.00294 kg pill)

The result from the given values will be the concentration in ppm.

Answer 2

The concentration of calcium ion in the pill is 15,340 ppm.

Step-by-step explanation:

To find the concentration of calcium ion (in ppm) in a 2.94 g pill that contains 45.1 mg of Ca² , we can use the formula:

Concentration (ppm) = (mass of solute / mass of solution) * 1,000,000

Concentration (ppm) = (45.1 mg / 2.94 g) * 1,000,000 = 15,340 ppm