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find the angle ACB of the given triangle with sides AB= 9cm and BC= 5cm. (give your answer to the nearest degree)​

find the angle ACB of the given triangle with sides AB= 9cm and BC= 5cm. (give your-example-1

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Explanation:

This is a law of sines problem.

Law of sines states that

A / sin (a) = B(sin b) = C (sin c)

5 / sin (60) = 9 / sin (x)

Simplifying this equation gives us sin (x) = (9 * sin (60)) / 5. Now we take the arc sin of both sides, to get that x = arc sin ((9 * sin (60)) / 5). Plugging this into a calculator gives us..... no solutions

I think thats the right solution as I plugged it into a law of sines calculator as well.

User Jchanger
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