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..................................................-example-1
User Lawinslow
by
8.2k points

2 Answers

2 votes

Answer:


x=\pm 9\:i

Explanation:

The given solutions of the quadratic equation 5x² + 405 = 0 are:


x=\pm \sqrt{(-405)/(5)}

To simplify the values of x, first divide 405 by 5:


x=\pm √(-81)

Rewrite -81 as 9² · -1:


x=\pm √(9^2 \cdot -1)


\textsf{Apply the radical rule:} \quad √(ab)=√(a)√(b)


x=\pm √(9^2)√( -1)


\textsf{Apply the radical rule:} \quad √(a^2)=a, \quad a \geq 0


x=\pm 9√( -1)


\textsf{Appl the imaginary number rule:}:\;√(-1)=i


\boxed{x=\pm 9\:i}

Therefore, the equivalent solutions to the given quadratic are x = ±9i.

User Saikou
by
8.5k points
0 votes

Answer:

x = ±9i

Explanation:

-405/5 = -81

sqrt(-81) = 9i

Answer: x = ±9i

User Ryan Angilly
by
8.4k points

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