10.4k views
4 votes
The quadratic function f(x) has roots of −4 and 3 and point (2, −6) lies on f(x). What is the equation of f(x)? f(x) = (x + 3)(x − 4) f(x) = (x − 3)(x + 4) f(x) = 3(x + 3)(x − 4) f(x) = 3(x − 3)(x + 4)

User Prasath V
by
8.6k points

1 Answer

6 votes

Answer:


\displaystyle{f(x)=(x+4)(x-3)}, the second choice.

Explanation:

Since the problem gives us that the quadratic function has roots of -4 and 3. Therefore, this means that:


\displaystyle{x=-4,3}

Which can be reverted back to:


\displaystyle{f(x)=(x+4)(x-3)}

However, we cannot assume that a = 1 in this case, so:


\displaystyle{f(x)=a(x+4)(x-3)}

To clear any confusions, a means how narrow or wide the graph is, the same a-term in standard form or vertex form.

As the point (2, -6) is said to lie on f(x), therefore, substitute x = 2 and y = -6 to solve for a:


\displaystyle{-6=a(2+4)(2-3)}\\\\\displaystyle{-6=a(6)(-1)}\\\\\displaystyle{-6=-6a}\\\\\displaystyle{a=1}

Therefore, a = 1. Thus, the equation of f(x) is:


\displaystyle{f(x)=(x+4)(x-3)}

User Imelgrat
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.