Answer:
AH=9
HC=40
Explanation:
In ΔABH
∡H=90°
AB=15
BH=12
AH=?
here we can use Pythagoras' theorem:
where a is base b is perpendicular and c is hypotenuse.
substituting value




Therefore: AH=9
In ΔACH
∡H=90°
AH=9
HC=?
∡C=30°
here also we can use Pythagoras' theorem:
where a is base b is perpendicular and c is hypotenuse.
substituting value


Therefore, HC=40