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A spinner with three equal size sections labeled red, green, and yellow is

spun once. Then a coin is tossed, and one of two cards labeled with a 1 or
a 2 is selected. What is the probability of spinning yellow, tossing heads,
and selecting the number 2?

FASTTT (ASAPPP!)

User Leongold
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1 Answer

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To find the probability of spinning yellow, tossing heads, and selecting the number 2, we need to multiply the probabilities of each individual event.

Given:

The spinner has three equal size sections labeled red, green, and yellow.
The coin has two sides labeled heads and tails.
The cards are labeled with a 1 and a 2.
The probability of spinning yellow is 1/3, as there are three equally likely outcomes and one of them is yellow.

The probability of tossing heads is 1/2, as there are two equally likely outcomes and one of them is heads.

The probability of selecting the number 2 is 1/2, as there are two cards and one of them is labeled with a 2.

To find the overall probability, we multiply the probabilities of each event:

P(Yellow, Heads, 2) = P(Yellow) * P(Heads) * P(2)
= (1/3) * (1/2) * (1/2)
= 1/12

Therefore, the probability of spinning yellow, tossing heads, and selecting the number 2 is 1/12.
User Ecbrodie
by
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