Answer: 11
Work Shown:
x = first integer
x+1 = second consecutive integer just after x
x+2 = third consecutive integer just after x+1
x+3 = fourth consecutive integer just after x+2
Add up those expressions
(x)+(x+1)+(x+2)+(x+3) = 4x+6
That sum is "16 less than 6 times the first integer", so,
sum = 6*(first) - 16
4x + 6 = 6x - 16
4x-6x = -16-6
-2x = -22
x = -22/(-2)
x = 11 is the first integer
The four consecutive integers are 11, 12, 13, 14.
As a check, the sum is 11+12+13+14 = 50
Then notice how 6x-16 = 6*11-16 = 50 to help confirm we have the correct answer.