Question

A triangle has side lengths of 5 cm, 8 cm and 10 cm. Determine the perimeter of the triangle and the area.

Answer 1

`\mathrm{23cm,19.81cm^2}`

Explanation:

`\mathrm{Solution:}\\\mathrm{Let\ a=5cm,\ b=8cm\ and\ c=10cm}\\\mathrm{Let\`

`\mathrm{Now,}\\\mathrm{Area\ of\ triangle=√(s(s-a)(s-b)(s-c))}\\\mathrm{=√(11.5(11.5-5)(11.5-8)(11.5-10))}\\\mathrm{=√(11.5* 6.5* 3.5* 1.5)}\\\mathrm{=19.81cm^2}\\\mathrm{So,\ the\ perimeter\ of \ the\ triangle\ is\ 23cm\ and\ area\ is\ 19.81cm^2.}`