Question

if it takes 38.70cm3 of 1.90M NaOH to neutralize 10.30cm3 of H2SO4 in a battery, what is the concentration of the H2SO4?​

Answer 1

To determine the concentration of H2SO4, we can use the concept of molarity (M) and the equation:

M1V1 = M2V2

where:

M1 = concentration of NaOH (in this case, 1.90 M)

V1 = volume of NaOH used (in this case, 38.70 cm^3)

M2 = concentration of H2SO4 (what we're trying to find)

V2 = volume of H2SO4 used (in this case, 10.30 cm^3)

Rearranging the equation, we have:

M2 = (M1 * V1) / V2

Substituting the given values:

M2 = (1.90 M * 38.70 cm^3) / 10.30 cm^3

M2 ≈ 7.12 M

Therefore, the concentration of H2SO4 is approximately 7.12 M.

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