To calculate the average vertical velocity for the time period between t = 0.00 s and t = 1.00 s, considering only the magnitude of the displacement, we can use the following formula:
Average vertical velocity = Magnitude of displacement / Time interval
For the first ball, we have:
Average vertical velocity = 2.70 m / 1.00 s = 2.70 m/s
For the second ball, we have:
Average vertical velocity = 2.75 m / 1.00 s = 2.75 m/s
Therefore, the second ball drops faster during the first second of the fall, as it has a higher average vertical velocity than the first ball. This result is consistent with the previous analysis where we considered the average vertical acceleration and the magnitude of the displacement separately.