Question

Part E For both Tracker experiments, calculate the average vertical velocityPart F For both Tracker experiments, calculate the average vertical acceleration, where the time period is t = 0.10 second to t = 1.00 second. Consider only the magnitude of the vertical velocity in the calculations. Record your results to three significant figures. Comment: How does the average acceleration of the two balls compare to the theoretical value of -9.81 meters/second2, and how do the accelerations of the two balls compare to each other? where the time period is t = 0.00 second to t = 1.00 second. Consider only the magnitude of the displacement. Record your results to three significant figures. Comment: Which ball drops faster during the first second of the fall?

Answer 1

The average vertical velocity and acceleration for the Tracker experiments are calculated from a ball's vertical displacement and velocity over time. A ball's average vertical acceleration should be close to -9.81 m/s², the acceleration due to gravity. Without details for a second ball, we cannot compare vertical velocities at t = 1.00 second but can assume equal acceleration in the absence of air resistance.

Step-by-step explanation:

To answer your questions about the Tracker experiments and the vertical motion of balls, we need to consider the given information and the physics concepts involved. For Part E, the average vertical velocity is calculated by taking the displacement in the vertical direction and dividing by the time taken to undergo that displacement. Given that the displacement is the area under the velocity-time graph for the vertical motion of the balls, we can examine each provided data point and graph accordingly to figure it out. Unfortunately, as the provided information is insufficient to calculate this directly, we will proceed with Part F.

For Part F, you are asked to calculate the average vertical acceleration during a specified time period. According to the graphical information, the ball's velocity goes from 4.90 m/s to -0.98 m/s within the given time range. Using the formula a = (Δv) / (Δt), where Δv is the change in velocity and Δt is the change in time, and considering the magnitude only, the average acceleration can be found. Since the acceleration due to gravity (-9.81 m/s²) is constant for any freely falling object, we expect the average vertical acceleration to be close to this value for both balls, regardless of other factors.

As for which ball drops faster during the first second of the fall, this is determined by looking at the vertical velocity values at t = 1.00 second. However, without specific data for a second ball, we can only reference the given acceleration and initial velocities to speculate that both balls would fall with the same acceleration due to gravity in the absence of air resistance.

Answer 2

To calculate the average vertical velocity and average vertical acceleration for the Tracker experiments, we need specific data regarding the velocities and positions of the balls at different time intervals. Unfortunately, you haven't provided any such data or specified the Tracker experiments you are referring to.

Additionally, you mentioned Part F, but there is no information provided for Part E, which makes it difficult to understand the full context of the experiment.

To provide accurate calculations and comparisons, please provide the necessary data, such as initial velocities, positions, and any other relevant information for the Tracker experiments.

Step-by-step explanation: