Question

Part E

For both Tracker experiments, calculate the average vertical velocity, where the time period is t = 0.00 second to t = 1.00 second. Consider only the magnitude of the displacement. Record your results to three significant figures.

Comment: Which ball drops faster during the first second of the fall?

small ball -0.000 Final Displacement -5.039
(at t =1.00)
large ball -0.000 final displacement -4.810

Answer 1

To calculate the average vertical velocity for the time period between t = 0.00 s and t = 1.00 s, considering only the magnitude of the displacement, we can use the formula:

Average vertical velocity = Magnitude of displacement / Time interval

For the small ball, we have:

Magnitude of displacement = |(-5.039 m) - 0 m| = 5.039 m

Average vertical velocity = 5.039 m / 1.00 s = 5.039 m/s

For the large ball, we have:

Magnitude of displacement = |(-4.810 m) - 0 m| = 4.810 m

Average vertical velocity = 4.810 m / 1.00 s = 4.810 m/s

Therefore, the small ball drops faster during the first second of the fall, as it has a higher average vertical velocity than the large ball. This result is consistent with the analysis of the magnitude of the displacement alone, where we found that the small ball had a larger displacement than the large ball.

Answer 2

To calculate the average vertical velocity for both Tracker experiments, we need to consider only the magnitude of the displacement and the time period from t = 0.00 seconds to t = 1.00 second.

The formula to calculate average velocity is:

Average Velocity = Displacement / Time

Given the magnitudes of displacement for the small ball and large ball:

For the small ball: Displacement = 5.039

For the large ball: Displacement = 4.810

The time period for both is 1.00 second.

Calculating the average vertical velocity for each ball:

For the small ball: Average Velocity = 5.039 / 1.00 = 5.039 m/s (rounded to three significant figures)

For the large ball: Average Velocity = 4.810 / 1.00 = 4.810 m/s (rounded to three significant figures)

Comment: During the first second of the fall, the small ball drops faster than the large ball, as it has a greater average vertical velocity.

Step-by-step explanation: