(−3x^2+5x-2)-2(x^2 — 2x − 1) In the expression above is rewritten in form ax^2+ bx +c, where a, b, and c are constants, what is the value of b?

Question

asked Jul 20, 2024 15.3k views

2 Answers

Saad Aleem · Answer 1 · 2024-07-24T19:41:06+0000

Answer:

b = 9

Explanation:

(-3x² + 5x - 2) - 2(x² - 2x - 1) =

= -3x² + 5x - 2 - 2x² + 4x + 2

= -5x² + 9x

= ax² + bx + c

a = -5; b = 9; c = 0

Answer: b = 9