Answer:
Ok So first let's find the A B 8 one we already the know 1 value so let's write it in algebraic expression which is:
8 + x + x + 1 = 15
2x + 9 = 15
2x = 15 - 9
2x = 6
x = 3
3 + 1 = 4
8 + 4 + 3 = 15
So Currently A is either 4 or 3 let's try with 4 first.
9 + 4 + x = 15
13 + x = 15
x = 15 - 13
x = 2
9 + 4 + 2 = 15
now, E is 2
7 + 2 + x = 15
9 + x = 15
x = 15 - 9
x = 6
7 + 2 + 6 = 15
now, F is 6
6 + 8 + x = 15
14 + x = 15
x = 15 - 14
x = 1
8 + 6 + 1 = 15
now, D is 1 and C is 5
I'm not gonna check diagonals Bit I'm pretty sure they will be correct so yeah A Is 4