ANSWER:
To determine which function has a larger maximum, we need to compare the vertex points of both functions.
For Function 1, the equation is f(x) = -3x^2 + 4x + 2. The coefficient of the x^2 term is negative, indicating that the parabola opens downward. The vertex of the parabola can be found using the formula x = -b / (2a), where a is the coefficient of x^2 (-3) and b is the coefficient of x (4).
Using the formula, we find that the x-coordinate of the vertex is x = -4 / (2 * -3) = 2/3. Substituting this value into the equation, we can find the corresponding y-coordinate: f(2/3) = -3(2/3)^2 + 4(2/3) + 2 = 4/3.
For Function 2, the given information states that the graph is a parabola that opens downward and passes through the points (-1/2, 0), (1/2, 4), and (2, 0). The vertex of this parabola can be found as the midpoint between the x-coordinates of the two known points with equal y-values. In this case, it would be the midpoint between (-1/2, 0) and (2, 0), which is (3/4, 0). Therefore, the maximum value is y = 0.
Comparing the y-values of the vertices, we see that f(2/3) = 4/3 and f(3/4) = 0. Since 4/3 is greater than 0, we can conclude that Function 1 has a larger maximum.
Therefore, the correct answer is:
a) Function 1 has a larger maximum.
IMPORTANT:
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