Question

Use the quadratic formula to find the exact solutions of 3x2 − 6x + 1 = 0.

x equals negative b plus or minus the square root of the quantity b squared minus 4 times a times c all over 2 times a

a
1 plus or minus 2 times the square root of 3 divided by 3
b
negative 1 plus or minus 2 times the square root of 3 divided by 3
c
1 plus or minus the square root of 6 divided by 3
d
negative 1 plus or minus the square root of 6 divided by 3

Answer 1

Hello!

`3x^(2) - 6x + 1 = 0\\\\x= \frac{-b \±\sqrt{b^(2)-4ac } }{2a} \\\\\\x = \frac{-(-6) \±\sqrt{(-6)^(2)-4*3*1 } }{2*3} \\\\\\x =(6 \±√(24 ) )/(6)\\\\\boxed{x =(3 \±√(6 ) )/(3)}`