Equation 1: Cost: y = mx + b
Where: y = total amount of money it will cost you
m = cost for producing 'x' amount of products
b = fixed start-up cost
Equation 2: Revenue: y = (price) x
Where: y = total amount of money you will make
(price) = the amount you are charging for each product
x = number of products you will sell
To solve this system of linear equations using the three methods discussed in class, we need to first set the two equations equal to each other:
mx + b = (price) x
We can rearrange this equation to solve for x:
mx - (price) x = -b
x(m - (price)) = -b
x = -b/(m - (price))
Now that we have solved for x, we can substitute this value into either of the original equations to solve for y. Let's use Equation 2:
y = (price) x
y = (price) (-b/(m - (price)))
y = -(price) b/(m - (price))
Therefore, the system of linear equations is:
Equation 1: y = mx + b
Equation 2: y = (price) x
Using the Graphing method, we can plot the two equations on a graph and find the point of intersection, which represents the solution to the system. However, since we donot have specific values for m, b, and the price, we cannot graph the equations.
Using the Substitution method, we can solve one of the equations for y and substitute it into the other equation. Let's solve Equation 1 for y:
y = mx + b
Now we can substitute this expression for y in Equation 2:
mx + b = (price) x
Simplifying this equation, we get:
(mx - (price) x) = -b
x(m - (price)) = -b
x = -b/(m - (price))
Now that we have solved for x, we can substitute this value back into either of the original equations to solve for y. Let's use Equation 1:
y = mx + b
y = m(-b/(m - (price))) + b
y = (mb/(price - m))
Therefore, the solution to the system of linear equations is:
x = -b/(m - (price))
y = (mb/(price - m))
Using the Elimination method, we can multiply Equation 1 by (price) and Equation 2 by -m, and then add the two equations together to eliminate y:
(price) y = (price)mx + (price) b
-m y = -(m price) x
(price - m) y = (price)mx - (m price) x + (price) b
(price - m) y = x((priceSorry, it seems that the last part of the equation got cut off in my previous response. Here is the correct version:
Using the Elimination method, we can multiply Equation 1 by (price) and Equation 2 by -m, and then add the two equations together to eliminate y:
(price) y = (price)mx + (price) b
-m y = -(m price) x
(price - m) y = x((price) - m) + (price) b
Now we can solve for y:
y = [x((price) - m) + (price) b] / (price - m)
And we can solve for x by using either Equation 1 or Equation 2:
x = -b/(m - (price))
Therefore, the solution to the system of linear equations is:
x = -b/(m - (price))
y = [x((price) - m) + (price) b] / (price - m)
Again, please note that these equations are general formulas and do not have specific values for m, b, and the price. You will need to substitute specific values into the equations to find the numerical solution.