Question

Question: The area of a trapezium is (6ah² + 9a) units². If the perpendicular height is (4h² + 6) units, express the sum of the lengths of the parallel sides in terms of a. Sum of the lengths of the parallel sides = ? units²​

Answer 1

3a units^2

Explanation:

Area = 6ah^2 + 9a = 1/2(b1 + b2) × (4h^2 + 6)

Simplify: 6ah^2 + 9a = 2h^2(b1 + b2) × 3(b1 + b2)

Factor out b1 + b2:

6ah^2 + 9a = (2h^2 + 3)(b1 + b2)

Express sum of lengths (divide both sides by 2h^2 + 3):

(b1 + b2) = 6a^2 + 9a / 2h^2 + 3

= 3 units^2

So, the sum of the lengths is 3 units^2 (in terms of a).