134k views
1 vote
QUESTION 6
Solve for a. (round to tenths)
8
a
14

QUESTION 6 Solve for a. (round to tenths) 8 a 14-example-1
User Vivy
by
8.1k points

2 Answers

2 votes
To solve this, use the Pythagorean theorem (a^2+b^2=c^2) as it is a right triangle.

Seeing that c^2 is occupied with a value, we would want to subtract c^2 (14) by b^2 (8) to figure out a^2.

Thusly, we come up with c^2 (14)^2 - b^2 (8)^2 = a^2

Once simplified, we get 196-64 = a^2, which is 132 = a^2.

Now, simplify once again by square rooting both sides of the equation.
By doing so, we get:

A = 11.5 (rounded to tenths).
User Ayushgp
by
8.7k points
1 vote

Answer:

11.5

Explanation:

Given:

Left side = 8

Bottom = a

Right side = 14

Using the Pythagorean theorem:


ax^(2) +
8x^(2) =
14x^(2)

Simplifying the equation:


ax^(2) + 64 = 196

Subtracting 64 from both sides:


ax^(2) = 132

Taking the square root of both sides:

a =
√(132)

Calculating the approximate value of "a":

a ≈ 11.5 (rounded to the nearest tenth)

Therefore, the value of "a" in the given right triangle is approximately 11.5.

User Sagi Forbes
by
9.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories