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What's the slope-intercept form of the equation of the line graphed in this figure?

A) y = –3∕5x + 1

B) y = –5∕ x – 1

C) y = 5∕3x + 1

D) y = 3∕5x + 1

What's the slope-intercept form of the equation of the line graphed in this figure-example-1
User Quickern
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1 Answer

3 votes

Answer:

Option D

Explanation:

Slope intercept form:

(-5, -2) ; x₁ = -5 & y₁ = -2

(5 , 4) ; x₂ = 5 & y₂ = 4

Plugin the points in the below mentioned formula and find the slope.


\boxed{\bf slope =(y_2-y_1)/(x_2-x_1)}


\sf = (4-[-2])/(5-[-5])\\\\\\=(4+2)/(5+5)\\\\=(6)/(10)\\\\=(3)/(5)

Equation of slope-intercept form: y =mx + b

Here, m is the slope and b is the y-intercept.


\sf y = (3)/(5)x + b

The line is passing through (5, 4). So, substitute the points in the equation and find the y-intercept.


4 =(3)/(5)*5 + b\\\\\\4=3+b\\\\

4 - 3 = b

b = 1

Slope intercept form of the equation:


\sf y = (3)/(5)x + 1

User Amdex
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