Answer:
it takes 6.75 hours
Explanation:
Since the time varies inversely with the speed v,we have
t ∝ 1/v
so the ratio between two values of times will be,
(t₁)/(t₂) = (1/v₁)÷(1/v₂) = (v₂)/(v₁)
(t₁)/(t₂) = (v₂)/(v₁)
in our case, it takes 6 hours at 900 km/h so t₁ = 6 h v₁ = 900 km/h
also, v₂ = 800 km/h
so we just need to find t₂,
putting values, we get,
(6/(t₂) = (800)/(900)
1/t₂ = 8/(9)(6)
1/t₂ = 4/(27)
t₂ = 27/4
t₂ = 6.75 hours