73.6k views
4 votes
Find the equation of the line passing through the points (-5,1) and (2.1) Write the equation in point-slope form

User Tomjung
by
7.9k points

1 Answer

3 votes

Hello !

Answer:


\Large \boxed{\sf y=1}

Explanation:

The slope-intercept form of a line is of the form
\sf y=mx+b where m is the slope and b is the y-intercept.

We're looking for the two coefficients m and b.

The lines passes through two points :

  • (-5,1)
  • (2,1)

Let's replace x and y with their values in the equation :


\begin{cases}\sf 1=-5m+b \\\sf 1=2m+b\end{cases}

We get a system of two linear equations to solve.

Let's subtract the second line from the first one and solve for m :


\sf 1-1=-5m+b-(2m+b)\\\iff 0=-5m+b-2m-b\\\iff 0=-7m\\\iff \boxed{\sf m=0}

Let's substitute 0 for m in the second equation :


\sf 1=2* 0+b\\\iff \boxed{\sf b=1}

The slope-intercept form of the line is :


\sf y=0x+1


\boxed{\sf y=1}

Have a nice day ;)

User Anderso
by
8.5k points

No related questions found