Explanation:
Let's solve the given questions step by step:
1. Determine the equation of f:
From the given information, we know that the turning point of f is (1, 4). The general form of a quadratic function is f(x) = ax^2 + bx + c. We are given that f(x) = a(x + p)^2 + q, so let's substitute the values:
f(x) = a(x + p)^2 + q
Since the turning point is (1, 4), we can substitute x = 1 and f(x) = 4 into the equation:
4 = a(1 + p)^2 + q
This gives us one equation involving a, p, and q.
2. Determine the equation of g:
The equation of g is given as g(x) = 0.3x + p1.
3. Determine the coordinates of the x-intercept of g:
The x-intercept is the point where the graph of g intersects the x-axis. At this point, the y-coordinate is 0.
Setting g(x) = 0, we can solve for x:
0 = 0.3x + p1
-0.3x = p1
x = -p1/0.3
Therefore, the x-intercept of g is (-p1/0.3, 0).
4. For which values of x will f(x) ≥ g(x)?
To determine the values of x where f(x) is greater than or equal to g(x), we need to compare their expressions.
f(x) = a(x + p)^2 + q
g(x) = 0.3x + p1
We need to find the values of x for which f(x) ≥ g(x):
a(x + p)^2 + q ≥ 0.3x + p1
Simplifying the equation will involve expanding the square and rearranging terms, but since the equation involves variables a, p, and q, we cannot determine the exact values without further information or constraints.
To summarize:
We have determined the equation of f in terms of a, p, and q, and the equation of g in terms of p1. We have also found the coordinates of the x-intercept of g. However, without additional information or constraints, we cannot determine the exact values of a, p, q, or p1, or the values of x for which f(x) ≥ g(x).