Question

the ∆hvap for benzene is 30.7 kj/mol at its boiling point of 80.0 °c. calculate w for the vaporization of one mole of benzene at this temperature.

Answer 1

To calculate the work for the vaporization of one mole of benzene at its boiling point with a given ∆Hvap of 30.7 kJ/mol, the work will be -30.7 kJ.

Step-by-step explanation:

The student is asking how to calculate the work (w) for the vaporization of one mole of benzene at its boiling point, given the enthalpy of vaporization (∆Hvap) is 30.7 kJ/mol. In this scenario, the work done by the system during vaporization at constant pressure is equal to the negative value of the enthalpy change. Thus, w = -∆Hvap.

For one mole of benzene vaporizing at its boiling point, w = -30.7 kJ/mol. Therefore, the work would be -30.7 kJ for the vaporization of one mole of benzene at 80.0 °C.