Question

Three integers have a mean of 10, a median of 12 and a range of 8.

Find the three integers.

Answer 1

The answers are

x=5

y=12

z=13

Explanation:

let the numbers be x,y,z

`(x + y + z)/(3) = 10`

`y = 12`

`z - x = 8`

z=8+x

x+12+x+8/3=10

2x+20/3=10

2x+20=30

2x=30-20

2x=10

divide both sides by 2

2x/2=10/2

x=5

z=8+5

z=13