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(2p²+7p-39)÷(2p-7)

Quotient ?

User TheDavil
by
7.8k points

2 Answers

7 votes

p + 7 should be it.

I am not 100% sure?

User Fakrul
by
8.0k points
3 votes

Answer:

Quotient: p + 7

Remainder: 10

Explanation:

To find the quotient of the expression (2p² + 7p - 39) ÷ (2p - 7), we can use long division or synthetic division. Let's use long division:

____________________

2p - 7 | 2p² + 7p - 39

We start by dividing the first term of the dividend by the first term of the divisor, which gives us 2p² ÷ 2p = p. We then multiply p by the divisor (2p - 7) and subtract it from the dividend:

p

____________________

2p - 7 | 2p² + 7p - 39

- (2p² - 7p)

14p - 39

____________________

2p - 7 | 2p² + 7p - 39

- (2p² - 7p)

___________

14p - 39

We repeat the process by dividing the first term of the new dividend (14p - 39) by the first term of the divisor (2p - 7). This gives us (14p - 39) ÷ (2p - 7) = 7. We then multiply 7 by the divisor (2p - 7) and subtract it from the new dividend:

p + 7

____________________

2p - 7 | 2p² + 7p - 39

- (2p² - 7p)

___________

14p - 39

- (14p - 49)

___________

10

We are left with a remainder of 10. Therefore, the quotient is p + 7 with a remainder of 10.

Quotient: p + 7

Remainder: 10

Hope this helps!

User Lavern
by
8.1k points